Medium
Cutting Ribbons — C++
Full explanation · Time O(nlogr) · Space O(1)
// Time: O(nlogr), r is sum(ribbons)/k
// Space: O(1)
class Solution {
public:
int maxLength(vector<int>& ribbons, int k) {
int64_t left = 1, right = accumulate(cbegin(ribbons), cend(ribbons), 0LL) / k;
while (left <= right) {
int mid = left + (right - left) / 2;
if (!check(ribbons, k, mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return right;
}
private:
bool check(const vector<int>& ribbons, int k, int s) {
return accumulate(cbegin(ribbons), cend(ribbons), 0LL,
[&s](auto total, auto x) {
return total + x / s;
}) >= k;
}
};