Medium
Course Schedule — Python
Full explanation · Time O(\ · Space V\
# Time: O(|V| + |E|)
# Space: O(|E|)
import collections
# Khan's algorithm (bfs solution)
class Solution(object):
def canFinish(self, numCourses, prerequisites):
"""
:type numCourses: int
:type prerequisites: List[List[int]]
:rtype: List[int]
"""
adj = collections.defaultdict(list)
in_degree = collections.Counter()
for u, v in prerequisites:
in_degree[u] += 1
adj[v].append(u)
result = []
q = [u for u in xrange(numCourses) if u not in in_degree]
while q:
new_q = []
for u in q:
result.append(u)
for v in adj[u]:
in_degree[v] -= 1
if in_degree[v] == 0:
new_q.append(v)
q = new_q
return len(result) == numCourses
# Time: O(|V| + |E|)
# Space: O(|E|)
import collections
# dfs solution
class Solution2(object):
def canFinish(self, numCourses, prerequisites):
"""
:type numCourses: int
:type prerequisites: List[List[int]]
:rtype: List[int]
"""
adj = collections.defaultdict(list)
in_degree = collections.Counter()
for u, v in prerequisites:
in_degree[u] += 1
adj[v].append(u)
result = []
stk = [u for u in xrange(numCourses) if u not in in_degree]
while stk:
u = stk.pop()
result.append(u)
for v in adj[u]:
in_degree[v] -= 1
if in_degree[v] == 0:
stk.append(v)
return len(result) == numCourses