Hard

Couples Holding HandsC++

Full explanation · Time O(n) · Space O(n)

// Time:  O(n)
// Space: O(n)

class Solution {
public:
    int minSwapsCouples(vector<int>& row) {
        int N = row.size() / 2;
        vector<vector<int>> couples(N);
        for (int seat = 0; seat < row.size(); ++seat) {
            couples[row[seat] / 2].emplace_back(seat / 2);
        }
        vector<vector<int>> adj(N);
        for (const auto& couple : couples) {
            adj[couple[0]].emplace_back(couple[1]);
            adj[couple[1]].emplace_back(couple[0]);
        }
        
        int result = 0;
        for (int couch = 0; couch < N; ++couch) {
            if (adj[couch].empty()) {
                continue;
            }
            int couch1 = couch;
            int couch2 = adj[couch1].back(); adj[couch1].pop_back();
            while (couch2 != couch) {
                ++result;
                adj[couch2].erase(find(adj[couch2].begin(), adj[couch2].end(), couch1));
                couch1 = couch2;
                couch2 = adj[couch1].back(); adj[couch1].pop_back();
            }
        }
        return result;  // also equals to N - (# of cycles)
    }
};