Easy
Counting Words With a Given Prefix — C++
Full explanation · Time O(n * p) · Space O(1)
// Time: O(n * p)
// Space: O(1)
// string
class Solution {
public:
int prefixCount(vector<string>& words, string pref) {
return count_if(cbegin(words), cend(words),
[&pref](const auto& x) {
return x.compare(0, size(pref), pref) == 0;
});
}
};