Hard
Count the Number of Arrays with K Matching Adjacent Elements — Python
Full explanation · Time O(n + logm) · Space O(n)
# Time: O(n + logm)
# Space: O(n)
# combinatorics, fast exponentiation
MOD = 10**9+7
FACT, INV, INV_FACT = [[1]*2 for _ in xrange(3)]
def nCr(n, k):
while len(INV) <= n: # lazy initialization
FACT.append(FACT[-1]*len(INV) % MOD)
INV.append(INV[MOD%len(INV)]*(MOD-MOD//len(INV)) % MOD) # https://cp-algorithms.com/algebra/module-inverse.html
INV_FACT.append(INV_FACT[-1]*INV[-1] % MOD)
return (FACT[n]*INV_FACT[n-k] % MOD) * INV_FACT[k] % MOD
class Solution(object):
def countGoodArrays(self, n, m, k):
"""
:type n: int
:type m: int
:type k: int
:rtype: int
"""
return (nCr(n-1, k)*(m*pow(m-1, (n-1)-k, MOD)))%MOD