Easy
Count Subarrays of Length Three With a Condition — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# array
class Solution(object):
def countSubarrays(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
return sum((nums[i-1]+nums[i+1])*2 == nums[i] for i in xrange(1, len(nums)-1))