Medium
Count Sub Islands — Python
Full explanation · Time O(m * n) · Space O(1)
# Time: O(m * n)
# Space: O(1)
class Solution(object):
def countSubIslands(self, grid1, grid2):
"""
:type grid1: List[List[int]]
:type grid2: List[List[int]]
:rtype: int
"""
directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]
def dfs(grid1, grid2, i, j):
if not (0 <= i < len(grid2) and
0 <= j < len(grid2[0]) and
grid2[i][j] == 1):
return 1
grid2[i][j] = 0
result = grid1[i][j]
for di, dj in directions:
result &= dfs(grid1, grid2, i+di, j+dj)
return result
return sum(dfs(grid1, grid2, i, j) for i in xrange(len(grid2)) for j in xrange(len(grid2[0])) if grid2[i][j])