Medium
Count Special Triplets — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// dp
class Solution {
public:
int specialTriplets(vector<int>& nums) {
static const int MOD = 1e9 + 7;
int result = 0;
vector<unordered_map<int, int>> dp(2);
for (const auto& x : nums) {
if (x % 2 == 0 && dp[1].count(x / 2)) {
result = (result + dp[1][x / 2]) % MOD;
}
if (dp[0].count(2 * x)) {
dp[1][x] = (dp[1][x] + dp[0][2 * x]) % MOD;
}
dp[0][x] = (dp[0][x] + 1) % MOD;
}
return result;
}
};
// Time: O(n)
// Space: O(n)
// freq table
class Solution2 {
public:
int specialTriplets(vector<int>& nums) {
static const int MOD = 1e9 + 7;
unordered_map<int, int> right;
for (const auto& x : nums) {
++right[x];
}
int result = 0;
unordered_map<int, int> left;
for (const auto& x : nums) {
--right[x];
if (!right[x]) {
right.erase(x);
}
if (left.count(2 * x) && right.count(2 * x)) {
result = (result + static_cast<int64_t>(left[2 * x]) * right[2 * x]) % MOD;
}
++left[x];
}
return result;
}
};