Medium

Count Special SubsequencesC++

Full explanation · Time O(n^2) · Space O(n^2)

// Time:  O(n^2)
// Space: O(n^2)

// freq table
class Solution {
public:
    long long numberOfSubsequences(vector<int>& nums) {
        int64_t result = 0;
        unordered_map<double, int> cnt;
        for (int r = 4; r + 2 < size(nums); ++r) {
            const int q = r - 2;
            for (int p = 0; p <= q - 2; ++p) {
                ++cnt[static_cast<double>(nums[p]) / nums[q]];
            }
            for (int s = r + 2; s < size(nums); ++s) {
                result += cnt[static_cast<double>(nums[s]) / nums[r]];
            }
        }
        return result;
    }
};

// Time:  O(n^2 * logr)
// Space: O(n^2)
// freq table, number theory
class Solution2 {
public:
    long long numberOfSubsequences(vector<int>& nums) {
        int64_t result = 0;
        unordered_map<int, unordered_map<int, int>> cnt;
        for (int r = 4; r + 2 < size(nums); ++r) {
            const int q = r - 2;
            for (int p = 0; p <= q - 2; ++p) {
                const int g = gcd(nums[p], nums[q]);
                ++cnt[nums[p] / g][nums[q] / g];
            }
            for (int s = r + 2; s < size(nums); ++s) {
                const int g = gcd(nums[s], nums[r]);
                result += cnt[nums[s] / g][nums[r] / g];
            }
        }
        return result;
    }
};