Hard
Count Special Integers — C++
Full explanation · Time O(logn) · Space O(logn)
// Time: O(logn)
// Space: O(logn)
// combinatorics
class Solution {
public:
int countSpecialNumbers(int n) {
const auto& P = [](int m, int n) {
int result = 1;
while (n--) {
result *= m--;
}
return result;
};
const auto& digits = to_string(n + 1);
int result = 0;
for (int i = 1; i < size(digits); ++i) {
result += P(9, 1) * P(9, i - 1);
}
unordered_set<int> lookup;
for (int i = 0; i < size(digits); ++i) {
for (int d = int(i == 0); d < digits[i] - '0'; ++d) {
if (lookup.count(d)) {
continue;
}
result += P(9 - i, size(digits) - i - 1);
}
if (lookup.count(digits[i] - '0')) {
break;
}
lookup.emplace(digits[i] - '0');
}
return result;
}
};