Medium

Count Servers that CommunicatePython

Full explanation · Time O(m * n) · Space O(m + n)

# Time:  O(m * n)
# Space: O(m + n)

class Solution(object):
    def countServers(self, grid):
        """
        :type grid: List[List[int]]
        :rtype: int
        """
        rows, cols = [0]*len(grid), [0]*len(grid[0])
        for i in xrange(len(grid)):
            for j in xrange(len(grid[0])):
                if grid[i][j]:
                    rows[i] += 1
                    cols[j] += 1
        result = 0
        for i in xrange(len(grid)):
            for j in xrange(len(grid[0])):
                if grid[i][j] and (rows[i] > 1 or cols[j] > 1):
                    result += 1
        return result