Easy
Count Prefix and Suffix Pairs I — C++
Full explanation · Time O(n * l) · Space O(t)
// Time: O(n * l)
// Space: O(t)
// trie
class Solution {
private:
class Trie {
public:
Trie()
: nodes_() {
new_node();
}
int add(const string& w) {
int result = 0, curr = 0;
for (int i = 0; i < size(w); ++i) {
const int k = (w[i] - 'a') * 26 + (w[size(w) - 1 - i] - 'a');
if (!nodes_[curr].count(k)) {
nodes_[curr][k] = new_node();
}
curr = nodes_[curr][k];
result += cnts_[curr];
}
++cnts_[curr];
return result;
}
private:
int new_node() {
nodes_.emplace_back();
cnts_.emplace_back(0);
return size(nodes_) - 1;
}
vector<unordered_map<int, int>> nodes_;
vector<int> cnts_;
};
public:
long long countPrefixSuffixPairs(vector<string>& words) {
int64_t result = 0;
Trie trie;
for (const auto& w : words) {
result += trie.add(w);
}
return result;
}
};
// Time: O(n^2 * l)
// Space: O(1)
// brute force
class Solution2 {
public:
long long countPrefixSuffixPairs(vector<string>& words) {
const auto& check = [&](int i, int j) {
return words[j].starts_with(words[i]) && words[j].ends_with(words[i]);
};
int64_t result = 0;
for (int i = 0; i < size(words); ++i) {
for (int j = i + 1; j < size(words); ++j) {
if (check(i, j)) {
++result;
}
}
}
return result;
}
};