Easy
Count Pairs Whose Sum is Less than Target — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
// sort, two pointers
class Solution {
public:
int countPairs(vector<int>& nums, int target) {
sort(begin(nums), end(nums));
int result = 0;
int left = 0, right = size(nums) - 1;
while (left < right) {
if (nums[left] + nums[right] < target) {
result += right - left;
++left;
} else {
--right;
}
}
return result;
}
};