Easy
Count Pairs Of Similar Strings — C++
Full explanation · Time O(n * l) · Space O(n)
// Time: O(n * l)
// Space: O(n)
// freq table, bitmask
class Solution {
public:
int similarPairs(vector<string>& words) {
int result = 0;
unordered_map<int, int> cnt;
for (const auto& w : words) {
int mask = 0;
for (const auto& c : w) {
mask |= 1 << (c - 'a');
}
result += cnt[mask]++;
}
return result;
}
};