Medium
Count Pairs of Equal Substrings With Minimum Difference — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int countQuadruples(string firstString, string secondString) {
vector<int> lookup1(26, -1);
for (int i = size(firstString) - 1; i >= 0; --i) {
lookup1[firstString[i] - 'a'] = i;
}
vector<int> lookup2(26, -1);
for (int i = 0; i < size(secondString); ++i) {
lookup2[secondString[i] - 'a'] = i;
}
int result = 0, diff = numeric_limits<int>::max();
for (int i = 0; i < 26; ++i) {
if (lookup1[i] == -1 || lookup2[i] == -1) {
continue;
}
if (lookup1[i] - lookup2[i] < diff) {
diff = lookup1[i] - lookup2[i];
result = 0;
}
result += int(lookup1[i] - lookup2[i] == diff);
}
return result;
}
};