Medium
Count Pairs in Two Arrays — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
class Solution {
public:
long long countPairs(vector<int>& nums1, vector<int>& nums2) {
for (int i = 0; i < size(nums1); ++i) {
nums1[i] -= nums2[i];
}
sort(begin(nums1), end(nums1));
long long result = 0;
int left = 0, right = size(nums1) - 1;
while (left < right) {
if (nums1[left] > 0 || -nums1[left] < nums1[right]) {
result += right - left;
--right;
} else {
++left;
}
}
return result;
}
};