Medium
Count Number of Bad Pairs — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
import collections
# freq table
class Solution(object):
def countBadPairs(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = len(nums)*(len(nums)-1)//2
cnt = collections.Counter()
for i, x in enumerate(nums):
result -= cnt[x-i]
cnt[x-i] += 1
return result