Easy
Count Negative Numbers in a Sorted Matrix — Python
Full explanation · Time O(m + n) · Space O(1)
# Time: O(m + n)
# Space: O(1)
class Solution(object):
def countNegatives(self, grid):
"""
:type grid: List[List[int]]
:rtype: int
"""
result, c = 0, len(grid[0])-1
for row in grid:
while c >= 0 and row[c] < 0:
c -= 1
result += len(grid[0])-1-c
return result