Medium
Count Lattice Points Inside a Circle — C++
Full explanation · Time O(n * r^2) · Space O(min(n * r^2, maxx * maxy))
// Time: O(n * r^2)
// Space: O(min(n * r^2, max_x * max_y))
// math, hash table
class Solution {
public:
int countLatticePoints(vector<vector<int>>& circles) {
int max_y = 0;
for (const auto& circle : circles) {
max_y = max(max_y, circle[1] + circle[2]);
}
unordered_set<int> lookup;
for (const auto& circle : circles) {
for (int i = -circle[2]; i <= circle[2]; ++i) {
for (int j = -circle[2]; j <= circle[2]; ++j) {
if (i * i + j * j <= circle[2] * circle[2]) {
lookup.insert((circle[0] + i) * (max_y + 1) + (circle[1] + j));
}
}
}
}
return size(lookup);
}
};
// Time: O(n * max_x * max_y)
// Space: O(1)
// math
class Solution2 {
public:
int countLatticePoints(vector<vector<int>>& circles) {
int max_x = 0, max_y = 0;
for (const auto& circle : circles) {
max_x = max(max_x, circle[0] + circle[2]);
max_y = max(max_y, circle[1] + circle[2]);
}
int result = 0;
for (int i = 0; i <= max_x; ++i) {
for (int j = 0; j <= max_y; ++j) {
for (const auto& circle : circles) {
if ((i - circle[0]) * (i - circle[0]) + (j - circle[1]) * (j - circle[1]) <= (circle[2]) * circle[2]) {
++result;
break;
}
}
}
}
return result;
}
};