Medium
Count K-th Roots in a Range — Python
Full explanation · Time O(logr * logk) · Space O(1)
# Time: O(logr * logk)
# Space: O(1)
# binary search, fast exponentiation
class Solution(object):
def countKthRoots(self, l, r, k):
"""
:type l: int
:type r: int
:type k: int
:rtype: int
"""
def binary_search_right(left, right, check):
while left <= right:
mid = left+(right-left)//2
if not check(mid):
right = mid-1
else:
left = mid+1
return right
def count(right):
return binary_search_right(0, right, lambda x: x**k <= right)-0+1
return count(r)-count(l-1)