Easy
Count Integers With Even Digit Sum — C++
Full explanation · Time O(logn) · Space O(1)
// Time: O(logn)
// Space: O(1)
// math
class Solution {
public:
int countEven(int num) {
const auto& parity = [](int x) {
int result = 0;
for (; x; x /= 10) {
result += x % 10;
}
return result % 2;
};
return (num - parity(num)) / 2;
}
};
// Time: O(logn)
// Space: O(1)
// math
class Solution2 {
public:
int countEven(int num) {
const auto& parity = [](int x) {
int result = 0;
for (; x; x /= 10) {
result += x % 10;
}
return result % 2;
};
int result = 0;
for (int i = 1; i <= num; ++i) {
result += static_cast<int>(parity(i) == 0);
}
return result;
}
};