Hard
Count Connected Subgraphs with Even Node Sum — Python
Full explanation · Time O((n + e) * 2^n) · Space O(n + e)
# Time: O((n + e) * 2^n)
# Space: O(n + e)
# bitmask, dfs
class Solution(object):
def evenSumSubgraphs(self, nums, edges):
"""
:type nums: List[int]
:type edges: List[List[int]]
:rtype: int
"""
def even(mask):
def popcount(x):
return bin(x).count('1')
return not popcount(mask&odd_mask)%2
def connected(mask):
i = next(i for i in xrange(len(nums)) if mask&(1<<i))
mask ^= 1<<i
stk = [i]
while stk:
u = stk.pop()
for v in adj[u]:
if not mask&(1<<v):
continue
mask ^= 1<<v
stk.append(v)
return not mask
adj = [[] for _ in xrange(len(nums))]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
odd_mask = reduce(lambda accu, x: accu|(1<<x), (i for i in xrange(len(nums)) if nums[i]), 0)
return sum(even(mask) and connected(mask) for mask in xrange(1, 1<<len(nums)))
# Time: O((n + e) * 2^n)
# Space: O(n + e)
# bitmask, dfs
class Solution2(object):
def evenSumSubgraphs(self, nums, edges):
"""
:type nums: List[int]
:type edges: List[List[int]]
:rtype: int
"""
def even(mask):
parity = 0
for i in xrange(len(nums)):
if not mask&(1<<i):
continue
parity ^= nums[i]
return not parity
def connected(mask):
i = next(i for i in xrange(len(nums)) if mask&(1<<i))
mask ^= 1<<i
stk = [i]
while stk:
u = stk.pop()
for v in adj[u]:
if not mask&(1<<v):
continue
mask ^= 1<<v
stk.append(v)
return not mask
adj = [[] for _ in xrange(len(nums))]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
return sum(even(mask) and connected(mask) for mask in xrange(1, 1<<len(nums)))