Medium
Count Complete Substrings — C++
Full explanation · Time O(26 + d * n) · Space O(26)
// Time: O(26 + d * n), d = len(set(word))
// Space: O(26)
// freq table, two pointers, sliding window
class Solution {
public:
int countCompleteSubstrings(string word, int k) {
const int d = size(unordered_set<char>(cbegin(word), cend(word)));
int result = 0, valid = 0;
vector<int> cnt(26);
for (int c = 1; c <= d; ++c) {
int left = 0;
for (int right = 0; right < size(word); ++right) {
const int curr = ++cnt[word[right] - 'a'];
valid += curr == k ? 1 : curr == k + 1 ? -1 : 0;
if (right - left + 1 == c * k + 1) {
const int curr = cnt[word[left++] - 'a']--;
valid -= curr == k ? 1 : curr == k + 1 ? -1 : 0;
}
if (valid == c) {
++result;
}
if (right + 1 == size(word) || abs(word[right + 1] - word[right]) > 2) {
while (left < right + 1) {
const int curr = cnt[word[left++] - 'a']--;
valid -= curr == k ? 1 : curr == k + 1 ? -1 : 0;
}
}
}
}
return result;
}
};