Easy
Count Binary Substrings — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int countBinarySubstrings(string s) {
auto result = 0, prev = 0, curr = 1;
for (int i = 1; i < s.length(); ++i) {
if (s[i - 1] != s[i]) {
result += min(prev, curr);
prev = curr, curr = 1;
} else {
++curr;
}
}
result += min(prev, curr);
return result;
}
};