Medium
Convert Sorted List to Binary Search Tree — Python
Full explanation · Time O(n) · Space O(logn)
# Time: O(n)
# Space: O(logn)
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
#
# Definition for singly-linked list.
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
class Solution(object):
head = None
# @param head, a list node
# @return a tree node
def sortedListToBST(self, head):
current, length = head, 0
while current is not None:
current, length = current.next, length + 1
self.head = head
return self.sortedListToBSTRecu(0, length)
def sortedListToBSTRecu(self, start, end):
if start == end:
return None
mid = start + (end - start) / 2
left = self.sortedListToBSTRecu(start, mid)
current = TreeNode(self.head.val)
current.left = left
self.head = self.head.next
current.right = self.sortedListToBSTRecu(mid + 1, end)
return current