Medium
Continuous Subarray Sum — Python
Full explanation · Time O(n) · Space O(k)
# Time: O(n)
# Space: O(k)
class Solution(object):
def checkSubarraySum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: bool
"""
count = 0
lookup = {0: -1}
for i, num in enumerate(nums):
count += num
if k:
count %= k
if count in lookup:
if i - lookup[count] > 1:
return True
else:
lookup[count] = i
return False