Contain Virus
Time O((m * n)^(4/3)) · Space O(m * n) · Official statement on LeetCode
Solutions
// Time: O((m * n)^(4/3)), days = O((m * n)^(1/3))
// Space: O(m * n)
class Solution {
public:
int containVirus(vector<vector<int>>& grid) {
int result = 0;
while (true) {
P_SET lookup;
vector<P_SET> regions, frontiers;
vector<int> perimeters;
for (int r = 0; r < grid.size(); ++r) {
for (int c = 0; c < grid[r].size(); ++c) {
const auto& p = make_pair(r, c);
if (grid[r][c] == 1 && lookup.count(p) == 0) {
regions.emplace_back();
frontiers.emplace_back();
perimeters.emplace_back();
dfs(grid, p, &lookup, ®ions, &frontiers, &perimeters);
}
}
}
if (regions.empty()) {
break;
}
int triage_idx = 0;
for (int i = 0; i < frontiers.size(); ++i) {
if (frontiers[i].size() > frontiers[triage_idx].size()) {
triage_idx = i;
}
}
for (int i = 0; i < regions.size(); ++i) {
if (i == triage_idx) {
result += perimeters[i];
for (const auto& p : regions[i]) {
grid[p.first][p.second] = -1;
}
continue;
}
for (const auto& p : regions[i]) {
for (const auto& d : directions) {
int nr = p.first + d.first;
int nc = p.second + d.second;
if (nr < 0 || nr >= grid.size() ||
nc < 0 || nc >= grid[nr].size()) {
continue;
}
if (grid[nr][nc] == 0) {
grid[nr][nc] = 1;
}
}
}
}
}
return result;
}
private:
template <typename T>
struct PairHash {
size_t operator()(const pair<T, T>& p) const {
size_t seed = 0;
seed ^= std::hash<T>{}(p.first) + 0x9e3779b9 + (seed<<6) + (seed>>2);
seed ^= std::hash<T>{}(p.second) + 0x9e3779b9 + (seed<<6) + (seed>>2);
return seed;
}
};
using P = pair<int, int>;
using P_SET = unordered_set<P, PairHash<int>>;
void dfs(const vector<vector<int>>& grid,
const P& p,
P_SET *lookup,
vector<P_SET> *regions,
vector<P_SET> *frontiers,
vector<int> *perimeters) {
if (lookup->count(p)) {
return;
}
lookup->emplace(p);
regions->back().emplace(p);
for (const auto& d : directions) {
int nr = p.first + d.first;
int nc = p.second + d.second;
if (nr < 0 || nr >= grid.size() ||
nc < 0 || nc >= grid[nr].size()) {
continue;
}
if (grid[nr][nc] == 1) {
dfs(grid, make_pair(nr, nc), lookup, regions, frontiers, perimeters);
} else if (grid[nr][nc] == 0) {
frontiers->back().emplace(nr, nc);
++perimeters->back();
}
}
}
const vector<P> directions = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
};
Beginner Explanation
What is Contain Virus?
Contain Virus (LeetCode #749) is a Hard problem that primarily trains depth first search.
How to think about it
- Restate the goal in your own words before coding.
- Work a tiny example by hand so the invariant becomes obvious.
- Identify the pattern — this problem aligns with dfs backtracking.
- Only then translate the idea into code.
Why this problem matters
Hard problems force you to combine patterns and prove complexity carefully — interview gold. Official solution notes mention: Simulation.
AlgoForge explanations are original teaching notes. Always open the official problem statement on LeetCode for constraints and examples.
Interview Walkthrough
Interview approach for Contain Virus
Opening (30–60 seconds)
- Clarify inputs/outputs and edge cases (empty input, single element, duplicates, overflow).
- State a brute force so the interviewer knows you can solve it naively.
- Propose the optimal direction tied to dfs backtracking.
Core solution narrative
- Define the state you track (pointers, DP cell, set membership, stack top, etc.).
- Explain the transition when you process the next element.
- Call out time (O((m * n)^(4/3))) and space (O(m * n)) before coding.
- Code cleanly; narrate variable names.
What interviewers listen for
- Correctness on edge cases
- Complexity honesty
- Ability to discuss trade-offs (e.g., hash map space vs. sort + two pointers)
Follow-up questions they may ask
- Can you solve it with less memory?
- What if the input stream is infinite / doesn't fit in RAM?
- How would tests look for adversarial inputs?
Optimized Approach
Optimized solution notes
The reference solutions on AlgoForge target O((m * n)^(4/3)) time and O(m * n) space.
Pattern focus: dfs backtracking
Use the pattern as a checklist:
- dfs backtracking — confirm the invariant holds after each step
Multiple methods appear in the source solutions — compare them and explain when each is preferable.
Implementation tips
- Prefer readable names over micro-optimizations in interviews.
- Extract helpers only when they clarify (e.g., expand-around-center, DFS visit).
- After AC-level logic, re-scan for off-by-one and null checks.
Complexity Analysis
Complexity
| Measure | Bound |
|---|---|
| Time | O((m * n)^(4/3)) |
| Space | O(m * n) |
How to justify this in an interview
- Time: count loops, map/set operations, and recursive branching; state average vs worst case if relevant.
- Space: include hash maps, recursion stack, and output allocation when the problem asks for it.
If your implementation differs from the reference, re-derive big-O from your code — never memorize a complexity you cannot defend.
Common Mistakes
Common mistakes on Contain Virus
- Skipping edge cases — empty collections, single-element inputs, max constraints.
- Wrong invariant for dfs backtracking — updating state too early or too late.
- Mutating input unexpectedly when the problem forbids it.
- Off-by-one in windows, ranges, or binary search bounds.
- Ignoring overflow / precision for integer arithmetic problems.
- Overengineering — jumping to an advanced structure when a simpler approach works.
Alternative Approaches
Alternatives
The source file includes more than one method. Compare:
- Primary optimized path — best complexity for typical interviews.
- Secondary approach — often brute force, sorting-based, or space-optimized variant.
Practice articulating when you would pick each (constraints, readability, follow-ups).
Edge Cases
Edge cases checklist
- Minimum input size
- Maximum input size / time limits
- Duplicates and already-sorted input
- Negative numbers / zeros (if applicable)
- Disconnected structures (graphs/trees)
- Single path vs branching recursion depth
Pattern Recognition
Spotting this pattern
Signal phrases that point to dfs backtracking:
- Sorted input or ability to sort without changing the answer class
- Need for contiguous subarray / substring → consider sliding window
- Need for O(1) membership → hash set/map
- Optimal substructure + overlapping subproblems → DP
- Connectivity / components → graph DFS/BFS or Union-Find
Primary topics: depth first search.
Follow-up Interview Questions
Follow-ups
- How does the solution change if the input is a stream?
- Can you solve it in-place?
- What if duplicates must be handled differently?
- How would you parallelize the approach?
- Design tests that would break a buggy implementation.
Practice Recommendations
What to practice next
- Re-solve Contain Virus in a second language (cpp, python).
- Drill 3–5 more problems tagged depth first search.
- Teach the solution out loud in under 5 minutes.
- Add this problem to your revision calendar in 3 days and 14 days.
Visualization
Study checklist
- Read the official problem statement on LeetCode
- Solve on paper / whiteboard first
- Implement the dfs backtracking approach
- Verify edge cases from the checklist
- State time and space complexity aloud
- Compare with the AlgoForge reference solution
- Schedule a revision session
Revision notes
Contain Virus (#749) — Hard. Pattern: dfs backtracking. Complexity: O((m * n)^(4/3)) time / O(m * n) space. Re-derive the invariant before coding.
FAQs
What is the time complexity of Contain Virus?+
The reference solutions aim for O((m * n)^(4/3)) time and O(m * n) space. Always re-derive complexity from the code you write in the interview.
What pattern does Contain Virus use?+
It primarily maps to dfs backtracking, within the broader topic of depth first search.
Is Contain Virus good for interviews?+
Yes — as a Hard problem it is a solid practice target. Pair it with related problems in the same pattern family for spaced repetition.
Where can I read the official statement?+
Open the official LeetCode page for constraints and examples: https://leetcode.com/problems/contain-virus/