Medium
Concatenation of Consecutive Binary Numbers — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def concatenatedBinary(self, n):
"""
:type n: int
:rtype: int
"""
MOD = 10**9+7
result = l = 0
for i in xrange(1, n+1):
if i&(i-1) == 0:
l += 1
result = ((result<<l)%MOD+i)%MOD
return result