Easy
Compute Alternating Sum — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// array
class Solution {
public:
int alternatingSum(vector<int>& nums) {
int result = 0, sign = 1;
for (const auto& x : nums) {
result += sign * x;
sign *= -1;
}
return result;
}
};