Hard
Closest Room — C++
Full explanation · Time O(nlogn + klogk + klogn) · Space O(n + k)
// Time: O(nlogn + klogk + klogn)
// Space: O(n + k)
class Solution {
public:
vector<int> closestRoom(vector<vector<int>>& rooms, vector<vector<int>>& queries) {
static const auto& by_size_desc = [](const auto& a, const auto& b) { return a[1] > b[1]; };
sort(begin(rooms), end(rooms), by_size_desc);
for (int i = 0; i < size(queries); ++i) {
queries[i].emplace_back(i);
}
sort(begin(queries), end(queries), by_size_desc);
set<int> ids;
vector<int> result(size(queries), -1);
int i = 0;
for (const auto& q : queries) {
int r = q[0], s = q[1], idx = q[2];
for (; i < size(rooms) && rooms[i][1] >= s; ++i) {
ids.emplace(rooms[i][0]);
}
result[idx] = find_closest(ids, r);
}
return result;
}
private:
int find_closest(const set<int>& ids, int r) {
int result = -1, min_diff = numeric_limits<int>::max();
auto it = ids.upper_bound(r);
if (it != begin(ids) && abs(*prev(it) - r) < min_diff) {
min_diff = abs(*prev(it) - r);
result = *prev(it);
}
if (it != end(ids) && abs(*it - r) < min_diff) {
min_diff = abs(*it - r);
result = *it;
}
return result;
}
};
// Time: O(nlogn + klogk + klogn)
// Space: O(n + k)
class Solution2 {
public:
vector<int> closestRoom(vector<vector<int>>& rooms, vector<vector<int>>& queries) {
static const auto& by_size_asc = [](const auto& a, const auto& b) { return a[1] < b[1]; };
sort(begin(rooms), end(rooms), by_size_asc);
for (int i = 0; i < size(queries); ++i) {
queries[i].emplace_back(i);
}
sort(begin(queries), end(queries), by_size_asc);
set<int> ids;
for (const auto& room : rooms) {
ids.emplace(room[0]);
}
vector<int> result(size(queries), -1);
int i = 0;
for (const auto& q : queries) {
int r = q[0], s = q[1], idx = q[2];
for (; i < size(rooms) && rooms[i][1] < s; ++i) {
ids.erase(rooms[i][0]);
}
result[idx] = find_closest(ids, r);
}
return result;
}
private:
int find_closest(const set<int>& ids, int r) {
int result = -1, min_diff = numeric_limits<int>::max();
auto it = ids.upper_bound(r);
if (it != begin(ids) && abs(*prev(it) - r) < min_diff) {
min_diff = abs(*prev(it) - r);
result = *prev(it);
}
if (it != end(ids) && abs(*it - r) < min_diff) {
min_diff = abs(*it - r);
result = *it;
}
return result;
}
};