Medium
Closest Divisors — C++
Full explanation · Time O(sqrt(n)) · Space O(1)
// Time: O(sqrt(n))
// Space: O(1)
class Solution {
public:
vector<int> closestDivisors(int num) {
vector<vector<int>> results = {divisors(num + 1), divisors(num + 2)};
return *min_element(cbegin(results), cend(results),
[](const auto& a, const auto& b) {
return a[1] - a[0] < b[1] - b[0];
});
}
private:
vector<int> divisors(int n) {
for (int d = sqrt(n); d >= 1; --d) {
if (n % d == 0) {
return {d, n / d};
}
}
return {1, n};
}
};
// Time: O(sqrt(n))
// Space: O(1)
class Solution2 {
public:
vector<int> closestDivisors(int num) {
vector<int> result = {1, num};
for (int d = 1; d * d <= num + 2; ++d) {
if ((num + 2) % d == 0) {
result = {d, (num + 2) / d};
}
if ((num + 1) % d == 0) {
result = {d, (num + 1) / d};
}
}
return result;
}
};