Easy
Check if Grid Satisfies Conditions — C++
Full explanation · Time O(m * n) · Space O(1)
// Time: O(m * n)
// Space: O(1)
// array
class Solution {
public:
bool satisfiesConditions(vector<vector<int>>& grid) {
for (int j = 0; j < size(grid[0]); ++j) {
for (int i = 0; i + 1 < size(grid); ++i) {
if (grid[i][j] != grid[i + 1][j]) {
return false;
}
}
if (j + 1 < size(grid[0]) && grid[0][j] == grid[0][j + 1]) {
return false;
}
}
return true;
}
};