Easy
Check if Array Is Sorted and Rotated — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
bool check(vector<int>& nums) {
for (int i = 0, count = 0; i < size(nums); ++i) {
if (nums[i] > nums[(i + 1) % size(nums)] && ++count > 1) {
return false;
}
}
return true;
}
};