Easy
Check if Array is Good — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
# freq table
class Solution(object):
def isGood(self, nums):
"""
:type nums: List[int]
:rtype: bool
"""
cnt = [0]*len(nums)
for x in nums:
if x < len(cnt):
cnt[x] += 1
else:
return False
return all(cnt[x] == 1 for x in xrange(1, len(nums)-1))