Easy
Check Balanced String — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# string
class Solution(object):
def isBalanced(self, num):
"""
:type num: str
:rtype: bool
"""
return sum(ord(num[i])-ord('0') for i in xrange(0, len(num), 2)) == sum(ord(num[i])-ord('0') for i in xrange(1, len(num), 2))