Medium
Candy Crush — C++
Full explanation · Time O((R * C)^2) · Space O(1)
// Time: O((R * C)^2)
// Space: O(1)
class Solution {
public:
vector<vector<int>> candyCrush(vector<vector<int>>& board) {
const auto R = board.size(), C = board[0].size();
bool changed = true;
while (changed) {
changed = false;
for (int r = 0; r < R; ++r) {
for (int c = 0; c + 2 < C; ++c) {
auto v = abs(board[r][c]);
if (v != 0 && v == abs(board[r][c + 1]) && v == abs(board[r][c + 2])) {
board[r][c] = board[r][c + 1] = board[r][c + 2] = -v;
changed = true;
}
}
}
for (int r = 0; r + 2 < R; ++r) {
for (int c = 0; c < C; ++c) {
auto v = abs(board[r][c]);
if (v != 0 && v == abs(board[r + 1][c]) && v == abs(board[r + 2][c])) {
board[r][c] = board[r + 1][c] = board[r + 2][c] = -v;
changed = true;
}
}
}
for (int c = 0; c < C; ++c) {
int empty_r = R - 1;
for (int r = R - 1; r >= 0; --r) {
if (board[r][c] > 0) {
board[empty_r--][c] = board[r][c];
}
}
for (int r = empty_r; r >= 0; --r) {
board[r][c] = 0;
}
}
}
return board;
}
};