Build Binary Expression Tree From Infix Expression — C++

// Time:  O(n)
// Space: O(n)

// Support +, -, *, /.
class Solution {
public:
    Node* expTree(string s) {
        static const unordered_map<char, int> precedence = {{'+', 0}, {'-', 0}, {'*', 1}, {'/', 1}};

        stack<Node *> operands;
        stack<char> operators;
        int64_t operand = 0;
        for (int i = 0; i < size(s); ++i) {
            if (isdigit(s[i])) {
                operand = operand * 10 + s[i] - '0';
                if (i + 1 == size(s) || !isdigit(s[i + 1])) {
                    operands.emplace(new Node(operand + '0'));
                    operand = 0;
                }
            } else if (s[i] == '(') {
                operators.emplace(s[i]);
            } else if (s[i] == ')') {
                while (!empty(operators) && operators.top() != '(') {
                    compute(&operands, &operators);
                }
                operators.pop();
            } else if (precedence.count(s[i])) {
                while (!empty(operators) && precedence.count(operators.top()) && 
                       precedence.at(operators.top()) >= precedence.at(s[i])) {
                     compute(&operands, &operators);
                }
                operators.emplace(s[i]);
            }
        }
        while (!empty(operators)) {
            compute(&operands, &operators);
        }
        return operands.top();
    }

private:
    template<typename T>
    void compute(stack<T> *operands, stack<char> *operators) {
        const auto right = operands->top(); operands->pop();
        const auto left = operands->top(); operands->pop();
        const char op = operators->top(); operators->pop();
        operands->emplace(new Node(op, left, right));
    }
};