Medium
Binary Trees With Factors — Python
Full explanation · Time O(n^2) · Space O(n)
# Time: O(n^2)
# Space: O(n)
class Solution(object):
def numFactoredBinaryTrees(self, A):
"""
:type A: List[int]
:rtype: int
"""
M = 10**9 + 7
A.sort()
dp = {}
for i in xrange(len(A)):
dp[A[i]] = 1
for j in xrange(i):
if A[i] % A[j] == 0 and A[i] // A[j] in dp:
dp[A[i]] += dp[A[j]] * dp[A[i] // A[j]]
dp[A[i]] %= M
return sum(dp.values()) % M