Medium
Binary Tree Upside Down — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
# @param root, a tree node
# @return root of the upside down tree
def upsideDownBinaryTree(self, root):
p, parent, parent_right = root, None, None
while p:
left = p.left
p.left = parent_right
parent_right = p.right
p.right = parent
parent = p
p = left
return parent
# Time: O(n)
# Space: O(n)
class Solution2(object):
# @param root, a tree node
# @return root of the upside down tree
def upsideDownBinaryTree(self, root):
return self.upsideDownBinaryTreeRecu(root, None)
def upsideDownBinaryTreeRecu(self, p, parent):
if p is None:
return parent
root = self.upsideDownBinaryTreeRecu(p.left, p)
if parent:
p.left = parent.right
else:
p.left = None
p.right = parent
return root