Easy
Binary Search — Python
Full explanation · Time O(logn) · Space O(1)
# Time: O(logn)
# Space: O(1)
class Solution(object):
def search(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
left, right = 0, len(nums)-1
while left <= right:
mid = left + (right-left)//2
if nums[mid] > target:
right = mid-1
elif nums[mid] < target:
left = mid+1
else:
return mid
return -1