Easy

Binary SearchPython

Full explanation · Time O(logn) · Space O(1)

# Time:  O(logn)
# Space: O(1)

class Solution(object):
    def search(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: int
        """
        left, right = 0, len(nums)-1
        while left <= right:
            mid = left + (right-left)//2
            if nums[mid] > target:
                right = mid-1
            elif nums[mid] < target:
                left = mid+1
            else:
                return mid
        return -1