Easy
Binary Search — C++
Full explanation · Time O(logn) · Space O(1)
// Time: O(logn)
// Space: O(1)
class Solution {
public:
int search(vector<int>& nums, int target) {
int left = 0, right = nums.size() - 1;
while (left <= right) {
auto mid = left + (right-left) / 2;
if (nums[mid] > target) {
right = mid - 1;
} else if (nums[mid] < target) {
left = mid + 1;
} else {
return mid;
}
}
return -1;
}
};