Easy
Apply Operations to an Array — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# inplace, array
class Solution(object):
def applyOperations(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
for i in xrange(len(nums)-1):
if nums[i] == nums[i+1]:
nums[i], nums[i+1] = 2*nums[i], 0
i = 0
for x in nums:
if not x:
continue
nums[i] = x
i += 1
for i in xrange(i, len(nums)):
nums[i] = 0
return nums