Medium
All Possible Full Binary Trees — Python
Full explanation · Time O(n * 4^n / n^(3/2)) · Space O(n * 4^n / n^(3/2))
# Time: O(n * 4^n / n^(3/2)) ~= sum of Catalan numbers from 1 .. N
# Space: O(n * 4^n / n^(3/2)) ~= sum of Catalan numbers from 1 .. N
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def __init__(self):
self.__memo = {1: [TreeNode(0)]}
def allPossibleFBT(self, N):
"""
:type N: int
:rtype: List[TreeNode]
"""
if N % 2 == 0:
return []
if N not in self.__memo:
result = []
for i in xrange(N):
for left in self.allPossibleFBT(i):
for right in self.allPossibleFBT(N-1-i):
node = TreeNode(0)
node.left = left
node.right = right
result.append(node)
self.__memo[N] = result
return self.__memo[N]