Medium
All Paths From Source to Target — C++
Full explanation · Time O(p + r * n) · Space O(n)
// Time: O(p + r * n), p is the count of all the possible paths in graph,
// r is the count of the result.
// Space: O(n)
class Solution {
public:
vector<vector<int>> allPathsSourceTarget(vector<vector<int>>& graph) {
vector<vector<int>> result;
vector<int> path{0};
dfs(graph, 0, &path, &result);
return result;
}
private:
void dfs(const vector<vector<int>>& graph,
int curr, vector<int> *path,
vector<vector<int>> *result) {
if (curr == graph.size() - 1) {
result->emplace_back(*path);
return;
}
for (const auto& node: graph[curr]) {
path->emplace_back(node);
dfs(graph, node, path, result);
path->pop_back();
}
}
};