Medium
Alert Using Same Key-Card Three or More Times in a One Hour Period — C++
Full explanation · Time O(nlogn) · Space O(n)
// Time: O(nlogn)
// Space: O(n)
class Solution {
public:
vector<string> alertNames(vector<string>& keyName, vector<string>& keyTime) {
static const int THRESHOLD = 3;
unordered_map<string, vector<int>> name_to_times;
for (int i = 0; i < size(keyName); ++i) {
int hour = stoi(keyTime[i].substr(0, 2));
int minute = stoi(keyTime[i].substr(3));
name_to_times[keyName[i]].emplace_back(hour * 60 + minute);
}
vector<string> result;
for (auto& [name, times] : name_to_times) {
sort(begin(times), end(times));
for (int left = 0, right = 0; right < size(times); ++right) {
while (times[right] - times[left] > 60) {
++left;
}
if (right - left + 1 >= THRESHOLD) {
result.emplace_back(name);
break;
}
}
}
sort(begin(result), end(result));
return result;
}
};