Medium
3 Sum Closest — Python
Full explanation · Time O(n^2) · Space O(1)
# Time: O(n^2)
# Space: O(1)
class Solution(object):
def threeSumClosest(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
result, min_diff = 0, float("inf")
nums.sort()
for i in reversed(xrange(2, len(nums))):
if i+1 < len(nums) and nums[i] == nums[i+1]:
continue
left, right = 0, i-1
while left < right:
total = nums[left]+nums[right]+nums[i]
if total < target:
left += 1
elif total > target:
right -= 1
else:
return target
if abs(total-target) < min_diff:
min_diff = abs(total-target)
result = total
return result